OBJECTIVE
The purpose of this
experiment is to was to prepared acetylsalicylic acid
INTRODUCTION
+ +
(salysilic acid)
(acetic anhydride)
(acetysalicylic acid) (acetic
acid)
From the chemical equation the acetysalicylic acid can be
prepared by the reaction between salysilic acid and acetic anhydride.In this
rection , the hydroxyl group from benzene ring was reacted with acetic acid to
form ester functional group , so this reaction is referred as esterification
reaction.Concentrated sulphuric acid is the catalyst in this experiment which
make the reaction is complete.Crystallization process was required in this
experiment because there is some impurities such as unreacted salysilic acid
and acetic anhydrate presence with the acetysalicylic acid.So the process is
needed to makesure there is ni impurities in the last product.
Thus the separation of acetysalisilic acid from other
materials was accomplished and the product also washed with distilled water
after the crystal was formed because the water can decrease the solubity of
acetysalicylic acid and dissolves the left impurities.
Recrystallization process was formed to more purify the
product.Methanol was used as solvent in order to prevent the decomposition of
salicylic acid because water can make aspirin partially decompose while heating
the solution.If the aspirin decompose , we cannot get the correct result for
this experiment.The impurities which is salicylic acid will decompose from
incomplete reaction with acetic anhydrate, so after recrystallization, there is
no impurities in the last product.
RESULT AND OBSERVATION
Mass of salicyclic acid = 2.0011 g
Mass of filter paper = 0.5595 g
Mass of watch glass = 59.3232 g
Total mass = 64.9764 g – 59.3232 g – 0.5595 g
=5.0937 g
Mass after recrytallization = 4.4081 g
Mass of crude product =5.0937 g - 4.4081 g
= 0.6856 g
C7H6O3
+ C4H6O3 C9H8O4
+ CH3COOH
Molar mass of salicylic
acid = 138.121 g/mol
Mass of salicylic acid =
2.0011 g
Number of mole of
salicylic acid = 2.0011 g / 138 .121
= 0.001449mol
1 mol of salicyclic acid react with 1 mol of acetic anhydride to produce
1 mol of acetylsalicylic acid
0.001449 mol of salicyclic acid react with 0.001449 mol of acetic
anhydride to produce 0.001449 mol of
acetylsalicylic acid
Theoretical yield of
acetylsalicyclic acid = 0.001449 mol x 180.157
= 2.610 g
Percentage yield of
acetylsalicyclic acid = (0.6856 g / 2.610 g) x 100%
= 26.29%
Result for ferric
chloride test
Test tube A = Colourless
solution change to purple solution in colour
Test tube b = colourless
solution change to violet solution in colour
Test tube c = There is
no change in colour which is colourless solution.
DISCUSSION
This experiment was
performed to prepared acetylsalicyclic acid . As we know acetylsalicyclic acid
is a drug that is widely used as an antipyretic agent that is to reduce fever
,as an analgesic agent which is to reduce pain and as an anti-inflammatory.Chemically
acetylsalicyclic acid is an ester.Esters are the products of the reaction of
acids with alcohols , as shown as from the balance chemical equation below :
+ +
(salysilic acid)
(acetic anhydride)
(acetysalicylic acid)
(acetic acid)
We use an acetic anhydride instead of an acetic
acid because the anhydride react with water to form acetic acid. There is the
formula to calculate the theoretical yield of the acetysalicyclic acid :
From the result the
theoretical yield for this experiment is 2.610 g while the actual yield is 0.6856
g .the percentage yield we get
is 26.29%.There is large different percentage yield of this experiment to
100%.There maybe error occur when the temperature required for on the step of
the experiment that is 50˚C , we do not maintained the temperature so the
reaction do not completely react.
There also may occur
error when we cut the filter paper , the pen ink may contaminated our product
so we need to make sure that we cut all the filter paper which contained the
ink.While we are doing experiment we should take care of some precaution.As we
know the acetic anhydride can causes severe burns and harmful to inhaled.We
should wear gloves when handling the acetic anhydride solution and handle it in
the fume board carefully.
The next experiment which is test of ferric
chloride purity. From the result that we obtained from the experiment :
Test tube A = Colourless solution change to purple solution in colour
Test tube b = colourless solution change to violet solution in colour
Test tube c = There is no change in colour which is colourless solution.
Ferric chloride do not
react with aspirin . It will react with salicylic acid which is used to synthesize aspirin . In
this light , adding an aqueous ferric chloride solution into a sample of
aspirin is a better way to see if there any unreacted salicylic acid which is
not react .A purple colour indicate the unreacted salicylic acid , so a purple
colour should not exhibit any color change. For test tube A and B salicylic
acid was added so the ferric chloride
was reacted with the salicylic acid added while in the test tube C salisylic
acid doesn’t added to the test.So there is no impurities exists in the product
of the experiment.
CONCLUSION
Acetylsalicylic acid
was prepared . The actual yield we obtained from the experiment is 0.6856
g while the theoretical yield we
calculated is 2.610 g.The percentage yield is 26.29%.From the ferric chloride
test , we can conclude that there is no impurities in the product of the
experiment.
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